5x^2+35x-990=0

Solution for 5x^2+35x-990=0 equation:

5x^2+35x-990=0

a = 5; b = 35; c = -990;
Δ = b2-4ac
Δ = 352-4·5·(-990)
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21025}=145$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-145}{2*5}=\frac{-180}{10}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+145}{2*5}=\frac{110}{10}
=11
$